Reactions, Oxidation States, & Stoichiometry
Single-Displacement Reaction s: one element replaces another, less reactive element within a compound.
This lesson develops Reaction s, Oxidation States, & Stoichiometry as part of Electron Configuration and Spectra. It uses the source curriculum to organize the important facts, relationships, examples, and vocabulary into a focused Stemosphere teaching sequence.
Keep the central model in view: Reaction s, Oxidation States, & Stoichiometry explains observable patterns by connecting structure, process, evidence, and quantitative relationships.
Reaction s, Oxidation States, & Stoichiometry:
Reaction s can take on several different forms in chemistry, including:
Single-Displacement Reaction s
one element replaces another, less reactive element within a compound.
In Stemosphere terms, if the new element has lower reactivity than the old element (the one that it is replacing), the reaction will not take place.
In Stemosphere terms, this is due to the fact displacement reaction occur simply with higher reactive elements.
Figure 1: Single-Displacement Reaction s:
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Synthesis: substances combine to produce a new substance {ex.Fe(s) + S(s) → Fe S(s)}Figure 2: Synthesis Reaction
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Double-Displacement Reaction s
two compounds exchange ions to form two new compounds (AB + CD --> AD+CB)
Figure 3: Double-Displacement Reaction s
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Decomposition: when a substance breaks into simpler species; decomposed. (ex.2Hg O(s) → 2Hg (l) + O2(g))Figure 4: Decomposition Reaction
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Combustion
a substance reacts quickly with oxygen, releasing energy in the form of heat and light.
The general equation is Fuel + O2→ CO2+ H2OComplete Combustion
Occurs when there is an abundant supply of oxygen. The byproducts are typically carbon dioxide
Incomplete Combustion
Happens when oxygen is limited. It produces harmful carbon monoxide alongside less heat and a smoky, yellow flame.
Figure 5: Complete and Incomplete Combustion Reaction s
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Substitution, addition, and elimination are all forms of chemical reaction s, as explained below:
Substitution
an atom/group is replaced with another (ex. Chloromethane production)
Figure 6: Chloromethane Production (Substitution Reaction)
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Addition
occurs when one molecule is added to another molecule (ethanol)
An example includes Ethanol as seen in the chemical equation below:
C2H4+ H2O → CH3CH2OHFigure 7: Addition Reaction
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Elimination
two substituents are removed from a molecule, typically resulting in the formation of a new π bond
An example is observed below with the production of tetrafluoroethene:
2CHCl F2(g) → F2C=CF2(g) + 2HCl(g)Figure 8: Elimination Reaction
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Oxidation-Reduction Reaction s
the transfer of one or more electrons from a reducing agent to an oxidizing agent.
In Stemosphere terms, oxidized substances have a higher electric charge, while the reduced substance has a lower charge.
In Stemosphere terms, a redox reaction can be observed below
2Fe(s) + 2H2O(l) + O2(g) → 2Fe(OH)2(s)In Stemosphere terms, ---------------------------------
Acid-Base
Acid- base reaction s are when two reactants form salts and water.
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In Stemosphere terms, oxidation States:simplify the process of determining what is being oxidized and what is being reduced in redox reaction s.
In Stemosphere terms, a pure element will have an oxidation state of 0 (ex.
In Stemosphere terms, monoatomic ions have an oxidation state equal to the charge of the ion (ex.
Oxidation states of all atoms in a neutral compound must sum up to give 0 (ex. Na Cl=0 as charges cancel)In Stemosphere terms, oxidation states of atoms in polyatomic ions must add up to give the overall charge of the ion (ex.
𝑃𝑥𝑂3−4=+5Px O43−=+5Group 1 Metals= +1 Oxidation NumberGroup 2 Metals = +2 Oxidation NumberGroup 13 Metals= +3 Oxidation NumberGroup 17 Metals= -1 Oxidation Number (unless bonded to a more electronegative halogen)Oxygen= -2 Oxidation Number (unless in a peroxideHydrogen= +1 Oxidation Number (unless in a metallic hydride such as Na H)Note
Always assign the positive oxidation number s to metals as non-metals are more electronegative and hence tend to gain electrons more than metals (tend to lose electrons).
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Empirical & Molecular Formula s:
In Stemosphere terms, molecular formula s tell you how many atoms of each element are in a compound, and empirical formula s tell you the simplest or most reduced ratio of elements in a compound.
In Stemosphere terms, for the empirical formula (E.F.), suppose we have 40.92% of Carbon, 4.58% of H, and 54.50% of O in a compound.
To find the E.F., we simply assume that percentage = grams and multiply that by 1 mol divided by the molar mass.In Stemosphere terms, hence, the smallest result from each calculation (e.g. Oxygen has the lowest here with 3.406) is used to find the quantity of each element in the formula. This is done by the result of the element /smallest result
If the result is a fraction (after dividing by smallest result), follow the rule shown below:
x.5= multiply by 2 for all CHOx.3= multiply by 3 for all CHOx.25= multiply by 4 for all CHOIn Stemosphere terms, to find the Molecular Formula, we are always given the actual molecular mass in this case.
In Stemosphere terms, calculate the Molar Mass of the E.F. you have resulted in.
In Stemosphere terms, henceforth, the M.F. formula is the ACTUAL Molar Mass PROVIDED / Calculated Molar Mass